Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-6 Law of Cosines - Lesson Check - Page 529: 2

Answer

$m \angle R = 82^{\circ}$

Work Step by Step

Let's set up the law of cosines to find $m \angle B$: $b^2 = a^2 + c^2 - 2ac$ cos $\angle B$ In this exercise, $a = \overline{RS}$, $b = \overline{QS}$, and $c = \overline{QR}$. We want to find the measure of $\angle R$, which is $\angle B$ in the formula. Let's plug in what we know: $37.6^2 = 25.2^2 + 31.9^2 - 2(31.9)(25.2)$ cos $m \angle R$ Evaluate exponents first, according to order of operations: $1413.76 = 635.04 + 1017.61 - 2(31.9)(25.2)$ cos $m \angle R$ Add to simplify on the right side of the equation: $1413.76 = 1652.65 - 2(31.9)(25.2)$ cos $m \angle R$ Multiply to simplify: $1413.76 = 1652.65 - 1607.76$ cos $m \angle R$ Subtract $1652.65$ from each side of the equation to move constants to the left side of the equation: $-238.89 = -1607.76$ cos $m \angle R$ Divide each side by $-1607.76$: cos $m \angle R$ = $\frac{-238.89}{-1607.76}$ Take $cos^{-1}$ to solve for $\angle R$: $m \angle R = 82^{\circ}$
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