Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-5 Law of Sines - Practice and Problem-Solving Exercises - Page 525: 8

Answer

$x \approx 19.1$ $x \approx 14.5$

Work Step by Step

First, let's find the measure of the third angle by using the triangle sum theorem: $m$ of third angle = $180 - (63 + 71)$ Evaluate what is in parentheses first: $m$ of third angle = $180 - (134)$ Subtract: $m$ of third angle = $46^{\circ}$ Now, we can use the law of sines to relate the three angles and sides to one another: $\frac{sin 63^{\circ}}{18} = \frac{sin 71^{\circ}}{x} = \frac{sin 46^{\circ}}{y}$ Let's just use the first two fractions to find the value of $x$: $\frac{sin 63^{\circ}}{18} = \frac{sin 71^{\circ}}{x}$ Multiply each side by $x$: $\frac{sin 63^{\circ}}{18}(x)$ = sin $71^{\circ}$ Divide each side of the equation by $\frac{sin 63^{\circ}}{18}$ to solve for $x$: $x \approx 19.1$ Now, let's turn our attention to $y$: $\frac{sin 63^{\circ}}{18} = \frac{sin 46^{\circ}}{y}$ Multiply each side by $y$: $\frac{sin 63^{\circ}}{18}(y)$ = sin $46^{\circ}$ Divide each side of the equation by $\frac{sin 63^{\circ}}{18}$ to solve for $x$: $x \approx 14.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.