Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-3 Trigonometry - Practice and Problem-Solving Exercises - Page 512: 44


csc $B = \frac{15}{12}$

Work Step by Step

If the secant ratio is the inverse of the cosine ratio, then we just reverse the sides in the cosine ratio to get the secant ratio. If sec $B$ = $\frac{adjacent}{hypotenuse}$, then: sec $B$ = $\frac{hypotenuse}{adjacent}$. . Let's look at angle $B$. The hypotenuse has a length of $15$, and the side adjacent to $B$ has a length of $12$. csc $B = \frac{15}{12}$
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