Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-2 Special Right Triangles - Lesson Check - Page 503: 4

Answer

$x = 6 \sqrt 3$

Work Step by Step

In a $30^{\circ}-60^{\circ}-90^{\circ}$ triangle, the hypotenuse is two times the shorter leg. Let's write an equation to solve for the length of the shorter leg: $12 = 2$(shorter leg) Divide each side by $2$ to solve for the shorter leg: shorter leg = $6$ We don't want the length of the shorter leg; we want the length of the longer leg. In a $30^{\circ}-60^{\circ}-90^{\circ}$ triangle, the longer leg is $\sqrt 3$ times the shorter leg. Let's write an equation to solve for the length of the longer leg: $x = \sqrt 3(6)$ Let's rewrite this: $x = 6 \sqrt 3$
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