## Geometry: Common Core (15th Edition)

3$\sqrt 2$
The Pythagorean Theorem says that $(leg_{1}) ^{2}$+$(leg_{2})^{2}$=$hypotenuse^{2}$. This formula is more commonly referred to as $a^{2}$+$b^{2}$=$c^{2}$ You are given the lengths of both legs as x and the length of the hypotenuse as 6. Substitute x in for a and b and 6 in for c. $a^{2}$+$b^{2}$=$c^{2}$ $x^{2}$+$x^{2}$=$6^{2}$ 2$x^{2}$=36 Divide both sides by 2. $x^{2}$=18 Take the square root of both sides to find the length of the missing side. a=b=3$\sqrt 2$