Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-1 The Pythagorean Theorem and It's Converse - Lesson Check - Page 495: 4


4$\sqrt 3$

Work Step by Step

The Pythagorean Theorem says that $(leg_{1}) ^{2}$+$(leg_{2})^{2}$=$hypotenuse^{2}$. This formula is more commonly referred to as $a^{2}$+$b^{2}$=$c^{2}$ You are given the lengths of one leg as 11 and the length of the hypotenuse as 12. Substitute 11 in for a and 13 in for c. $a^{2}$+$b^{2}$=$c^{2}$ $11^{2}$+$b^{2}$=$13^{2}$ 121+$b^{2}$=169 Subtract 121 from both sides $b^{2}$=48 Take the square root of both sides to find the length of the missing side b=4$\sqrt 3$
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