Geometry: Common Core (15th Edition)

6$\sqrt 3$
The Pythagorean Theorem says that $(leg_{1}) ^{2}$+$(leg_{2})^{2}$=$hypotenuse^{2}$. This formula is more commonly referred to as $a^{2}$+$b^{2}$=$c^{2}$ You are given the lengths of one leg as 6 and the length of the hypotenuse as 12. Substitute 6 in for a and 12 in for c. $a^{2}$+$b^{2}$=$c^{2}$ $6^{2}$+$b^{2}$=$12^{2}$ 36+$b^{2}$=144 Subtract 36 from both sides. $b^{2}$=108 Take the square root of both sides to find the length of the missing side. b=6$\sqrt 3$