Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - Algebra Review - Page 439: 6


$\frac{3}{4}$, -$\frac{1}{2}$

Work Step by Step

$8x^{2}$-2x-3=0 Factor: (4x-3)(2x+1)=0 Set each factor equal to 0: 4x-3=0 4x=3 x=$\frac{3}{4}$ 2x+1=0 2x=-1 x=-$\frac{1}{2}$
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