Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-5 Proportions in Triangles - Practice and Problem-Solving Exercises - Page 478: 64

Answer

$AC$ = $16$ $m^2$ $CB$ = $16$ $m^2$ $BA$ = $32$ $m^2$

Work Step by Step

All we are asked to do is square each of the sides. Remember to square the units as well: First side: $AC$ = $($4$ m)^2$ Square both the value and the unit: $AC$ = $16$ $m^2$ Second side: $CB$ = $($4$ m)^2$ Square both the value and the unit: $CB$ = $16$ $m^2$ Third side: $BA$ = $($4$\sqrt 2$$ m)^2$ Square both the value and the unit: $BA$ = $16\sqrt {(2)(2)}$ $m^2$ Multiply what is inside brackets first: $BA$ = $16\sqrt {4}$ $m^2$ Take the square root of $4$: $BA$ = $16(2)$ $m^2$ Multiply to solve: $BA$ = $32$ $m^2$
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