Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-5 Proportions in Triangles - Practice and Problem-Solving Exercises - Page 476: 34

Answer

$x = 2.5$

Work Step by Step

According to the triangle-angle-bisector theorem, when a ray bisects the angle of a triangle, the opposite side is divided into two segments that are proportional to the remaining two sides of the triangle. Let's set up a proportion that compares the segments of the intersected side to the other two sides: $\frac{5x}{6x} = \frac{7x}{10x - 4}$ Use the cross product property to get rid of the fractions: $5x(10x - 4) = 6x(7x)$ Use the distributive property: $50x^2 - 20x = 42x^2$ Subtract $42x^2$ from each side to move all terms to the left side of the equation: $50x^2 - 42x^2 - 20x = 0$ Combine like terms: $8x^2 - 20x = 0$ Factor out $4$ from each term: $2x^2 - 5x = 0$ Factor out $x$ from the left side of the equation: $x(2x - 5) = 0$ Set each factor equal to $0$: $x = 0$ or $2x - 5 = 0$ We can discard $x = 0$ because we cannot have lengths equal to $0$. Let's look at the other factor: $2x - 5 = 0$ Add $5$ to each side of the equation: $2x = 5$ Divide each side of the equation by $2$ to solve for $x$: $x = 2.5$
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