Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-3 Providing Triangles Similar - Practice and Problem-Solving Exercises - Page 458: 50


The extremes are $12$ and $20$. The means are $m$ and $18$. $m = \frac{40}{3}$

Work Step by Step

A proportion takes the following form: $\frac{a}{b} = \frac{c}{d}$, where $a$ and $d$ are the extremes and $b$ and $c$ are the means. In this exercise, $a = 12$, $b = m$, $c = 18$, and $d = 20$. The extremes are $12$ and $20$. The means are $m$ and $18$. Let's solve for $m$: $\frac{12}{m} = \frac{18}{20}$ Use the cross products property to get rid of the fractions: $18m = 240$ Divide each side by $18$ to solve for $m$: $m = \frac{240}{18}$ Divide both the numerator and denominator by their greatest common factor, $6$: $m = \frac{40}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.