Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-2 Similar Polygons - Practice and Problem-Solving Exercises - Page 444: 14

Answer

Yes, the triangles are similar. $\triangle JKL ∼ \triangle PQR$ The scale factor is $\frac{2}{1}$ or $2:1$.

Work Step by Step

First, we identify all the pairs of congruent angles: $\angle K ≅ \angle Q$ $\angle J ≅ \angle P$ $\angle L ≅ \angle R$ Now, let's take a look at the corresponding sides in both triangles: $\frac{JK}{PQ} = \frac{16}{8}$ Divide the numerator and denominator by their greatest common factor, $8$: $\frac{JK}{PQ} = 2$ Let's look at $KL$ and $QR$: $\frac{KL}{QR} = \frac{34}{17}$ Divide the numerator and denominator by their greatest common factor, $17$: $\frac{KL}{QR} = 2$ Let's look at $LJ$ and $RP$: $\frac{LJ}{RP} = \frac{30}{15}$ Divide the numerator and denominator by their greatest common factor, $15$: $\frac{LJ}{RP} = 2$ $\triangle JKL ∼ \triangle PQR$ because all angles are congruent, and all sides are proportional. The scale factor is $\frac{2}{1}$ or $2:1$.
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