Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-1 Ratios and Proportions - Practice and Problem-Solving Exercises - Page 438: 58


4 or -3

Work Step by Step

$\frac{x-3}{3}$=$\frac{2}{x+2}$ Cross multiply 3(2)=(x-3)(x+2) 6=$x^{2}$-x-6 0=$x^{2}$-x-12 Factor (x-4)(x+3)=0 Set each factor to 0 to find solutions for x: x-4=0 x=4 x+3=0 x=-3
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.