Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-1 Ratios and Proportions - Practice and Problem-Solving Exercises: 58

Answer

4 or -3

Work Step by Step

$\frac{x-3}{3}$=$\frac{2}{x+2}$ Cross multiply 3(2)=(x-3)(x+2) 6=$x^{2}$-x-6 0=$x^{2}$-x-12 Factor (x-4)(x+3)=0 Set each factor to 0 to find solutions for x: x-4=0 x=4 x+3=0 x=-3
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