Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-1 Ratios and Proportions - Practice and Problem-Solving Exercises - Page 437: 34



Work Step by Step

By looking at the graph, you can determine EC is 8 units. You can also tell that AC is 6 units long. To figure out AE's length, calculate using the Pythagorean theorem. $AC^{2}$ + $EC^{2}$ = $AE^{2}$ $6^{2}$ + $8^{2}$ = $AE^{2}$ 36+64=$AE^{2}$ 100=$AE^{2}$ 10=AE Write the ratio of the sides. $\frac{AE}{EC}$=$\frac{10}{8}$ Reduce by dividing the numerator and denominator by 2. $\frac{5}{4}$
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