## Geometry: Common Core (15th Edition)

$\frac{5}{3}$
Given $\frac{9}{5}$=$\frac{3}{x}$ Cross multiply and solve for x: 9x=5(3) 9x=15 x=$\frac{15}{9}$ Reduce by dividing the numerator and denominator by 3: $\frac{15}{9}$=$\frac{5}{3}$