Answer
$A$
Work Step by Step
The diagonals of a parallelogram bisect one another; therefore, we can set the two bisected segments of each diagonal equal to one another. Let's start with the diagonal in which the segments have the same variable:
$3x - 2 = 5x - 6$
Subtract $5x$ from each side of the equation to move variables to the left side of the equation:
$-2x - 2 = -6$
Add $2$ to each side of the equation to move constants to the right side of the equation:
$-2x = -4$
Divide both sides by $-2$ to solve for $x$:
$x = 2$
Now, we can set the other two segments on the other diagonal equal to one another:
$6y - 4 = y + 1$
Add $4$ to each side of the equation to move constants to the right side of the equation:
$6y = y + 5$
Subtract $y$ from each side of the equation to move variables to the left side of the equation:
$5y = 5$
Divide both sides of the equation by $5$ to solve for $y$:
$y = 1$
