## Geometry: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 6 - Polygons and Quadrilaterals - 6-8 Applying Coordinate Geometry - Practice and Problem-Solving Exercises - Page 410: 8

#### Answer

Vertex $O$ is at $(0, 0)$. Vertex $S$ has coordinates $(0, a)$. Vertex $W$ has coordinates $(a, 0)$. Vertex $T$ has coordinates $(a, a)$.

#### Work Step by Step

A square would have sides of equal lengths; in this case, our square has sides of length $a$ each. Vertex $O$ is at the origin at $(0, 0)$. Vertex $S$ has no $x$ value, but the $y$ value is equal to the length $a$. Therefore, vertex $S$ has coordinates $(0, a)$. Vertex $W$ has an $x$ value equal to the length $a$, but there is no $y$ value. Therefore, vertex $W$ has coordinates $(a, 0)$. Vertex $T$ has an $x$ value equal to the length $a$ and a $y$ value equal to the length $a$ as well. Therefore, vertex $T$ has coordinates $(a, a)$.

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