Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - 6-5 Conditions for Rhombuses, Rectangles, and Squares - Practice and Problem-Solving Exercises - Page 386: 13

Answer

$x = 10$

Work Step by Step

According to theorem 6-18, the diagonals of a rectangle are congruent; therefore, the two diagonals shown are congruent to one another. Let's set the two expressions equal to one another: $4x - 7 = 2x + 13$ Subtract $2x$ from each side of the equation to move variables to the left side of the equation: $2x - 7 = 13$ Add $7$ to each side of the equation to move constants to the right side of the equation: $2x = 20$ Divide both sides by $2$ to solve for $x$: $x = 10$
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