Answer
$m \angle 1 = 40^{\circ}$
$m \angle 2 = 90^{\circ}$
$m \angle 3 = 50^{\circ}$
Work Step by Step
The diagonals of a rhombus bisect pairs of opposite angles; therefore, $m \angle 3 = 50$.
We can multiply $m \angle 3$ by $2$ to find the entire angle that was bisected by the diagonal. This angle would be $2(50)$ or $100^{\circ}$.
In a parallelogram, consecutive angles are supplementary; therefore, the angle that is consecutive to this angle is $180 - 100$ or $80^{\circ}$. This angle is bisected by a diagonal, giving rise to $\angle 1$ and an unnamed angle. $m \angle 1$ would be half of $80^{\circ}$ or $40^{\circ}$.
The diagonals of a rhombus bisect each other at right angles; therefore, $m \angle 2 = 90^{\circ}$.
