Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - 6-1 The Polygon Angle-Sum Theorems - Practice and Problem-Solving Exercises - Page 357: 31

Answer

This polygon has $20$ sides. m interior $\angle = 162^{\circ}$

Work Step by Step

If we have the measure of one exterior angle, we can find the number of sides this regular polygon has using the following formula. We'll use $n$ as the number of sides in this polygon: $18 = \frac{360}{n}$ Multiply each side of the equation by $n$ to get rid of the fraction: $18n = 360$ Divide each side by $18$ to solve for $n$: $n = 20$ This polygon has $20$ sides. To find the measure of an interior angle, we can use the corollary to the polygon angle-sum theorem, which states the following formula: m interior $\angle = \frac{(n - 2)(180)}{n}$ We know that $n$, the number of sides, for this polygon is $20$, so let's plug this piece of information in: m interior $\angle = \frac{(20 - 2)(180)}{20}$ Evaluate parentheses first: m interior $\angle = \frac{18(180)}{20}$ Multiply to simplify: m interior $\angle = \frac{3240}{20}$ Divide by $20$ to solve: m interior $\angle = 162^{\circ}$
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