Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - Mid-Chapter Quiz - Page 316: 10

Answer

$QB = 9$ $QP = 3$

Work Step by Step

A centroid is the point where all the medians of a triangle meet. The median is said to be concurrent at point $P$. The centroid also divides the median into two parts where the one part coming from the vertex is two-thirds of the median and the other part attaching to the side opposite the vertex makes up one-third of the median. We can then say that $PB$ is two-thirds of $QB$ and $QP$ is one-third of $BP$. Let's set up an equation to find $QB$: $PB = \frac{2}{3}(QB)$ Let's plug in what we know: $6 = \frac{2}{3}(QB)$ Let's divide each side by $\frac{2}{3}$, meaning we multiply by its reciprocal, $\frac{3}{2}$: $QB = 6(\frac{3}{2})$ Multiply to solve: $QB = \frac{18}{2}$ Divide both the numerator and denominator by their greatest common factor, $2$: $QB = 9$ We know that $QP$ is one-third of $QB$, so let's set up the equation to find $QP$: $QP = \frac{1}{3}(9)$ Multiply: $QP = \frac{9}{3}$ Divide the numerator and denominator by their greatest common factor, $3$: $QP = 3$
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