Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - Chapter Review - Page 343: 20


$m \angle XZY = 25^{\circ}$

Work Step by Step

If $P$ is the incenter, that means this is the point where all angle bisectors meet. Because $\angle XZY$ is bisected by $\overline{PZ}$, $\angle XZY$ is the sum of $\angle PZX$ and $\angle PZY$. So we need to find the measure of $\angle XZY$ to figure out the measure of $\angle PZX$. We already know the measures of $\angle YXZ$, which is $90^{\circ}$, and $\angle XYZ$, which is $40^{\circ}$. We also know that the measures of the interior angles of a triangle add up to $90^{\circ}$, so if we subtract the sum of the two known angles from $180^{\circ}$, then we'll find the measure of $\angle XZY$. Let's set up the equation using this information: $m \angle XZY = 180 - (m \angle YXZ + m \angle XYZ)$ Let's plug in our "knowns": $m \angle XZY = 180 - (90 + 40)$ Evaluate what's in parentheses first, according to order of operations: $m \angle XZY = 180 - (130)$ Subtract to solve: $m \angle XZY = 50$ $m \angle PZX$ is half of $m \angle XZY$; therefore, $m \angle XZY$ is $25^{\circ}$.
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