Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - 5-3 Bisectors in Triangles - Lesson Check - Page 304: 2

Answer

$x = 6$

Work Step by Step

$T$ marks the point of concurrency of a triangle's angle bisectors. Therefore, $T$ is the center of the circle that is inscribed inside the triangle, so any point on that circle is equidistant from $T$. In this diagram, $U$ and $V$ are located on the inscribed circle; therefore, $TU$ is equal to $TV$. We can now set these distances equal to one another to solve for $x$: $3x - 12 = 5x - 24$ Subtract $3x$ from each side of the equation to isolate the variable on one side of the equation: $-12 = 2x - 24$ Add $24$ to each side of the equation to isolate constants on one side of the equation: $2x = 12$ Divide each side of the equation by $2$ to solve for $x$: $x = 6$
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