Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - 5-2 Perpendicular and Angle Bisectors - Practice and Problem-Solving Exercises - Page 297: 17

Answer

$y = 3$ Both $ST$ and $TU$ are 15.

Work Step by Step

The angle bisector theorem states that a point that is located on an angle's bisector is equidistant from the angle's sides. In this diagram, we see that $\overline{TV}$ is the angle bisector of $\angle SVU$. Therefore, $T$, which is a point on the bisector, is equidistant from the sides of the angle. So, $T$ is equidistant from $\overline{VS}$ and $\overline{VU}$. Therefore, $\overline{ST}$ is equal to $\overline{TU}$. Let's set $ST$ and $TU$ equal to one another to find the value of $y$: $5y = 3y + 6$ Subtract $3y$ from each side to isolate the variable on one side of the equation: $2y = 6$ Divide each side of the equation by $2$ to solve for $y$: $y = 3$ $ST = TU = 5y$ Plug in $3$ for $y$: $ST = TU = 5(3)$ Multiply to solve: $ST = TU = 15$
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