Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - 5-2 Perpendicular and Angle Bisectors - Practice and Problem-Solving Exercises - Page 296: 8

Answer

$JM = 9$

Work Step by Step

According to the perpendicular bisector theorem, points lying on the perpendicular bisector of a segment are equidistant from the segment's endpoints. In the diagram, we see that $\overline{MB}$ is the perpendicular bisector of $\overline{JK}$; therefore, $M$ is equidistant from $J$ and $K$. $JM$, thus, is equal to $KM$. We set these two line segments equal to one another to find $x$: $JM = KM$ Let's plug in what we know: $9x - 18 = 3x$ Add $18$ to both sides of the equation to isolate constants on the right side of the equation: $9x = 3x + 18$ Subtract $3x$ from each side of the equation to isolate the variable on the left side of the equation: $6x = 18$ Divide each side by $6$ to solve for $x$: $x = 3$ Now that we have the value of $x$, we can plug it into the expression to find $JM$: $JM = 9x - 18$ Plug in $3$ for $x$: $JM = 9(3) - 18$ Multiply first, according to order of operations: $JM = 27 - 18$ Subtract to find $JM$: $JM = 9$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.