Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - 5-1 Midsegments of Triangles - Practice and Problem-Solving Exercises - Page 288: 13

Answer

$\overline{AC}$

Work Step by Step

$\overline{AG}$ is congruent to $\overline{GB}$, meaning the midpoint of $\overline{AB}$ occurs at point $G$; $\overline{CE}$ is congruent to $\overline{EB}$, meaning the midpoint of $\overline{CB}$ occurs at point $E$. Therefore, $\overline{GE}$ joins $\overline{CB}$ at its midpoint $E$ and $\overline{AB}$ at its midpoint $G$. According to the triangle midsegment theorem, if a line segment joins two sides of a triangle at their midpoints, then that line segment is parallel to the third side of that triangle and is half as long as that third side. Knowing this information, we can deduce that $\overline{AC}$, which is the third side, is parallel to $\overline{GE}$, which is the line segment. $\overline{GE} \parallel \overline{AC}$
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