Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 4 - Congruent Triangles - Get Ready! - Page 215: 5


$m\angle M$ is $90^{\circ}$, and $m\angle N$ is $90^{\circ}$.

Work Step by Step

If we know that $\angle M$ is supplementary to $\angle N$ and that they are congruent, then let's have $x$ be the measure of one angle and $2x$ be the measure of both angles. If we set $2x$ equal to $180$, then we have the measure of one of the angles: $2x = 180$ Divide each side by $2$ to solve for $x$: $x = 90$ $m\angle M$ is $90^{\circ}$, and $m\angle N$ is $90^{\circ}$.
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