Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 4 - Congruent Triangles - 4-1 Congruent Figures - Practice and Problem-Solving Exercises - Page 222: 28

Answer

$128^{\circ}$

Work Step by Step

If $ABCD$ is congruent to $EFGH$, then $m \angle DCB$ is congruent to $m \angle HGF$. If $m \angle HGF$ is $128^{\circ}$, then $m \angle DCB$ is also $128^{\circ}$.
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