Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 3 - Parallel and Perpendicular Lines - Chapter Test - Page 211: 16


$$y-11 = 3(x-3)$$

Work Step by Step

We first find the slope: $$m = \frac{y_2-y_1}{x_2-x_1}$$ $$m = \frac{11-5}{3-1}= 3$$ We then use point slope form. Plugging in either point will work here: $$y_2-y_1=m(x_2-x_1)$$ $$y-11 = 3(x-3)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.