Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 3 - Parallel and Perpendicular Lines - 3-4 Parallel and Perpendicular Lines - Practice and Problem-Solving Exercises - Page 168: 21

Answer

$a$ is perpendicular to $d$. or, $a \perp d$

Work Step by Step

We are given that $b \perp c$ , thus according to definition of perpendicular lines, we have: $m \angle 2 =90$ We are given that $a \parallel c$ , thus according to corresponding angles postulate, we have: $m (\angle 1) =m (\angle 2)$ We are given that $c \parallel d$ , thus according to corresponding angles postulate, we have: $m (\angle 3) =m (\angle 1)$ We need to use transitive property of equality. This implies that $m (\angle 3) =m (\angle 1)=m (\angle 2)=90$ According to definition of perpendicular lines, we have: $m (\angle 3) =90$ So, $a$ is perpendicular to $d$. or, $a \perp d$
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