Answer
522.6 yd
Work Step by Step
The diameter of the semi-circle at each end of the track is:
$d=60+15+15=90$
The radius is half that, or 45.
The two semi-circles combine to make one whole circle. Find the perimeter.
$p=2\pi r=2(3.14)(45)=282.6$
Add the perimeter of the circular area to the lengths of the 2 straight edges.
$p=282.6+120+120=522.6$
