#### Answer

56

#### Work Step by Step

This is given by:
$_{8}C_5$
We know that:
$_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$
$_{8}C_5 = \frac{8!}{(8-5)!5!}$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
56

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Published by
Prentice Hall

ISBN 10:
0133281159

ISBN 13:
978-0-13328-115-6

56

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