Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 12 - Circles - 12-1 Tangent Lines - Got It? - Page 765: 3



Work Step by Step

Applying the Pythagorean theorem, we find: $$ x^2+100=\left(x+6\right)^2 \\ x^2-\left(x^2+12x\right)=x^2+12x-64-\left(x^2+12x\right) \\ -12x=-64 \\ x=\frac{16}{3}$$
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