#### Answer

$9 \pi \ m^2$

#### Work Step by Step

Let $A$ be the area of a circle. The area $(A)$ of a circle whose radius is $R$ is given by: $A=\pi r^2 ...(1)$
We know that the radius id half of the diameter of a circle. That is, $r=\dfrac{d}{2}=\dfrac{6}{2}=3$
Plug the data in the equation (1) to obtain:
$A=\pi (3)^2=\pi(9)$
Therefore, we get , $Area=9 \pi \ m^2$