Chapter 10 - Area - 10-7 Areas of Circles and Sectors - Practice and Problem-Solving Exercises - Page 663: 7

$9 \pi \ m^2$

Let $A$ be the area of a circle. The area $(A)$ of a circle whose radius is $R$ is given by: $A=\pi r^2 ...(1)$ We know that the radius id half of the diameter of a circle. That is, $r=\dfrac{d}{2}=\dfrac{6}{2}=3$ Plug the data in the equation (1) to obtain: $A=\pi (3)^2=\pi(9)$ Therefore, we get , $Area=9 \pi \ m^2$