Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-2 Areas of Trapezoids, Rhombuses, and Kites - Practice and Problem-Solving Exercises - Page 626: 19

Answer

72 $m^{2}$

Work Step by Step

First, find the base length of the triangle pictured. $a^{2}$+$b^{2}$=$c^{2}$ $8^{2}$+$b^{2}$=$10^{2}$ 64+$b^{2}$=100 $b^{2}$=36 b=6 Add this to the portion of the base given: 6+6=12. This is now your $b_{1}$. The figure shows you that $b_{2}$=6. We use the formula for the area of a trapezoid to obtain: A=$\frac{1}{2}$h($b_{1}$+$b_{2}$) A=$\frac{1}{2}$(8)(12+6) A=$\frac{1}{2}$(8)(18) A=72
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