Chapter 10 - Area - 10-2 Areas of Trapezoids, Rhombuses, and Kites - Got It? - Page 625: 4

96$cm^{2}$

Work Step by Step

You need to find the length of the other diagonal. Use the Pythagorean Theorem. You know one side of the right triangle is 8 cm (1/2 of 16), and the hypotenuse is 10 cm. $a^{2}$+$b^{2}$=$c^{2}$ $8^{2}$+$b^{2}$=$10^{2}$ 64+$b^{2}$=100 $b^{2}$=36 b=6 The shorter diagonal is twice the length just found: 6 x 2=12 A=$\frac{1}{2}$$d^{1}$$d^{2}$ A=$\frac{1}{2}$(16)(12) A=96

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