Answer
The area will be doubled.
Work Step by Step
The area of the original shape above (comprised of a triangle and square) is 60 in$^{2}$. If the base lengths of the square and triangle were doubled, the area of the individual shapes would change as follows:
triangle area = $\frac{1}{2}$bh = $\frac{1}{2}$(12)8 = 48 in$^{2}$
square area = bh = 12(6) = 72 in$^{2}$
area of the figure = 48 in$^{2}$ + 72 in$^{2}$ = 120 in$^{2}$
The area has doubled from 60 in$^{2}$ to 120 in$^{2}$.
