# Chapter 10 - Area - 10-1 Areas of Parallelograms and Triangles - Got It? - Page 618: 4

The area will be doubled.

#### Work Step by Step

The area of the original shape above (comprised of a triangle and square) is 60 in$^{2}$. If the base lengths of the square and triangle were doubled, the area of the individual shapes would change as follows: triangle area = $\frac{1}{2}$bh = $\frac{1}{2}$(12)8 = 48 in$^{2}$ square area = bh = 12(6) = 72 in$^{2}$ area of the figure = 48 in$^{2}$ + 72 in$^{2}$ = 120 in$^{2}$ The area has doubled from 60 in$^{2}$ to 120 in$^{2}$.

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