Answer
perimeter is 32 in
area is 40 in$^2$
Work Step by Step
The figure has 8 sides. 4 have a length of 5 in. 4 have a length of 3 in.
The perimeter is the sum of the lengths of all the sides.
$P=4(5)+4(3)=20+12=32$
Use the Area Addition Postulate to find the area of the figure. The figure consists of one 5 square with a side of 5 in and a 3 in X 5 in rectangle. Find the area of each.
$A_1=s^2=5^2=25$
$A_2=bh=(3)(5)=15$
sum to find the total area
$A=A_1+A_2=25+15=40$
