## Geometry: Common Core (15th Edition)

perimeter is 32 in area is 40 in$^2$
The figure has 8 sides. 4 have a length of 5 in. 4 have a length of 3 in. The perimeter is the sum of the lengths of all the sides. $P=4(5)+4(3)=20+12=32$ Use the Area Addition Postulate to find the area of the figure. The figure consists of one 5 square with a side of 5 in and a 3 in X 5 in rectangle. Find the area of each. $A_1=s^2=5^2=25$ $A_2=bh=(3)(5)=15$ sum to find the total area $A=A_1+A_2=25+15=40$