## Geometry: Common Core (15th Edition)

$d=2.8$ $M(-4,-4)$
Use the distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ $d=\sqrt{(-3-(-5))^2+(-5-(-3))^2}$ $d=\sqrt{(2)^2+(-2)^2}$ $d=\sqrt{4+4}$ $d=\sqrt{8}$ $d\approx2.8$ Use the midpoint formula to find the x-coordinate of the midpoint: $x_m=\frac{x_1+x_2}{2}=\frac{-5+(-3)}{2}=\frac{-8}{2}=-4$ Use the midpoint formula to find the y-coordinate of the midpoint: $y_m=\frac{y_1+y_2}{2}=\frac{-3+(-5)}{2}=\frac{-8}{2}=-4$