Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Review Exercises - Page 447: 19

Answer

V=120$\pi$

Work Step by Step

h$_{cone}$=$\sqrt {5^2-3^2}$=4 h$_{cylinder}$=17-4-3=10 V=$\frac{2}{3}$$\pi$3$^3$+$\pi$3$^2$(10)+$\frac{1}{3}$$\pi$3$^2$(4) V=18$\pi$+90$\pi$+12$\pi$ V=120$\pi$
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