Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 392: 34a

Answer

r=3

Work Step by Step

These three numbers form a pythagorean triple so this is a right triangle. r=$\frac{ab}{a+b+c}$ r=$\frac{120}{8+15+17}$ r=$\frac{120}{40}$ r=3 r=$\frac{2\sqrt {s(s-a)(s-b)(s-c)}}{a+b+c}$
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