Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 360: 25a

Answer

300$ft^{2}$

Work Step by Step

We need to find the area of the wall. Wall can be divided into rectangle and a triangle Area of wall = area of rectangle + area of triangle Area of rectangle whose base has length b and height has length h is given by A =bh From the given diagram b= 24 ft h = 10 ft Area of rectangle = bh = 24 ft * 10 ft = 240 $ft^{2}$ Area of triangle whose base has length b and altitude has length h is given by A = $\frac{1}{2}$ bh From given diagram base b = 24 h = 15 -10 = 5 ft Area = $\frac{1}{2}$ * 24 * 5 = 60 $ft^{2}$ Therefore area of the wall = 60 + 240 = 300$ft^{2}$
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