Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Review Exercises - Page 399: 19

Answer

A=96$\sqrt 3$$\approx$166.3 ft$^2$

Work Step by Step

a=.5s$\sqrt 3$ a=4$\sqrt 3$ A=.5aP A=.5(4$\sqrt 3$)(48) A=96$\sqrt 3$$\approx$166.3
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