Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 6 - Section 6.4 - Some Constructions and Inequalities for the Circle - Exercises - Page 315: 37

Answer

7

Work Step by Step

We first find OM: $OM =\sqrt{13^2-12^2} = 5$ We now find ON: $ON = \sqrt{13^2-5^2} =12$ Thus: $MN = ON - OM = 12 - 5 =7$
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