Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 6 - Review Exercises: 24g

Answer

$\sqrt{45}$

Work Step by Step

We use the theorems in the chapter to obtain: $EC CD = AC BC \\ 2ED(CD) = 3(30)$ We know CD and ED are equal, so we find: $2ED^2 = 90 \\ ED = \sqrt{45}$
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