Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 267: 29

Answer

RK=1$\frac{4}{9}$

Work Step by Step

$\frac{RK}{KT}$$\times$$\frac{TH}{HS}$$\times$$\frac{GS}{RG}$=1 $\frac{RK}{3}$$\times$$\frac{5}{4}$$\times$$\frac{4}{3}$=1 5RK=9 RK=1$\frac{4}{9}$
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