Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 267: 24

Answer

AC=2$\sqrt 6$$\approx$4.9

Work Step by Step

$\frac{AD}{AC}$=$\frac{AC}{DB}$ $\frac{4}{AC}$=$\frac{AC}{6}$ AC$^2$=24 AC=2$\sqrt 6$$\approx$4.9
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