# Chapter 3 - Section 3.2 - Corresponding Parts of Congruent Triangles - Exercises: 32c

BS=24ft

#### Work Step by Step

Given: support system of a bridge which has AC=6ft m$\angle$ABC=28$^{\circ}$ AC=CD=VT=TR= 6ft because they are corresponding angles of congruent triangles also DV=AD AD=AC+CD AD=6ft +6ft AD=12ft DV=AD=12ft BS=CD+DV+VT BS=6+12+6 BS=24ft therefore, m$\angle$ABD=m$\angle$ABC+m$\angle$CBD m$\angle$ABD=28$^{\circ}$+28$^{\circ}$ m$\angle$ABD=56$^{\circ}$

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