Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 97: 14


m$\angle 1= 106^{\circ}$ m$\angle 4=51^{\circ}$ m$\angle 5= 51^{\circ}$

Work Step by Step

m$\angle 1= 180^{\circ}-m\angle 2$ because supplementary angles m$\angle 1= 180^{\circ}-74^{\circ}=106^{\circ}$ m$\angle 1=m\angle 3+m\angle 4$ m$\angle 4 =m\angle 1-m\angle3$ m$\angle 4=106^{\circ}-55^{\circ}=51^{\circ}$ m$\angle 5=m\angle 4$ alternate interior angles m$\angle 5= 51^{\circ}$
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