Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 2 - Section 2.1 - The Parallel Postulate and Special Angles - Exercises - Page 79: 13d

Answer

m$\angle$MOQ=34$^{\circ}$

Work Step by Step

Angles 5 and MON are supplementary. m$\angle$MON=180-m$\angle$5 m$\angle$MON=180-112 m$\angle$MON=68$^{\circ}$ Angle MOQ is equal to half of angle MON because ray OQ bisects angle MON. m$\angle$MOQ=$\frac{1}{2}$(m$\angle$MON) m$\angle$MOQ=$\frac{1}{2}$(68) m$\angle$MOQ=34$^{\circ}$
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